(3x-2)(2x^2+x-1)=0

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Solution for (3x-2)(2x^2+x-1)=0 equation: 


Simplifying
(3x + -2)(2x2 + x + -1) = 0

Reorder the terms:
(-2 + 3x)(2x2 + x + -1) = 0

Reorder the terms:
(-2 + 3x)(-1 + x + 2x2) = 0

Multiply (-2 + 3x) * (-1 + x + 2x2)
(-2(-1 + x + 2x2) + 3x * (-1 + x + 2x2)) = 0
((-1 * -2 + x * -2 + 2x2 * -2) + 3x * (-1 + x + 2x2)) = 0
((2 + -2x + -4x2) + 3x * (-1 + x + 2x2)) = 0
(2 + -2x + -4x2 + (-1 * 3x + x * 3x + 2x2 * 3x)) = 0
(2 + -2x + -4x2 + (-3x + 3x2 + 6x3)) = 0

Reorder the terms:
(2 + -2x + -3x + -4x2 + 3x2 + 6x3) = 0

Combine like terms: -2x + -3x = -5x
(2 + -5x + -4x2 + 3x2 + 6x3) = 0

Combine like terms: -4x2 + 3x2 = -1x2
(2 + -5x + -1x2 + 6x3) = 0

Solving
2 + -5x + -1x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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